If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-80=0
a = 4; b = 0; c = -80;
Δ = b2-4ac
Δ = 02-4·4·(-80)
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{5}}{2*4}=\frac{0-16\sqrt{5}}{8} =-\frac{16\sqrt{5}}{8} =-2\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{5}}{2*4}=\frac{0+16\sqrt{5}}{8} =\frac{16\sqrt{5}}{8} =2\sqrt{5} $
| 6x-15+4=45 | | p²-16=-16 | | 8y-5=2+19 | | 10/m+1=4m | | 6(t+3=42 | | b²+8b=0 | | 23=36/x | | 8x-9=40+15 | | (m-4)(m-4)=0 | | 5(x+3)+2=5x+17. | | w-5.8=1.36 | | 224=14-x | | x=5*4-4 | | 7m^=3-5m^2+8m-9 | | x=5*3-4 | | 2(x+4)+3(x-10)=18 | | x=5*2-4 | | x=52-4 | | F(v)=100(v=100) | | 11-5=k | | 5x-8/13=x/3 | | x=5-1-4 | | 5g+3=38 | | x=5-4-4 | | 2m*2+9m+9=0 | | X=2(x+4)+3(x-10)=18 | | (X+1)=(x+8) | | (4-2z)/3=3/4-5z-6 | | 6-3y=32 | | 74x-37=74x-3774x−37=74x−37 | | 7x(3+2)=9(x-1) | | 8x-15=6x-5 |