4x2-93-(1-9x)-(3-8x)=2(2x+1)(x-1)

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Solution for 4x2-93-(1-9x)-(3-8x)=2(2x+1)(x-1) equation: 



4x^2-93-(1-9x)-(3-8x)=2(2x+1)(x-1)

We move all terms to the left:

4x^2-93-(1-9x)-(3-8x)-(2(2x+1)(x-1))=0

We add all the numbers together, and all the variables

4x^2-(-9x+1)-(-8x+3)-(2(2x+1)(x-1))-93=0

We get rid of parentheses

4x^2+9x+8x-(2(2x+1)(x-1))-1-3-93=0

We multiply parentheses ..

4x^2-(2(+2x^2-2x+x-1))+9x+8x-1-3-93=0



We calculate terms in parentheses: -(2(+2x^2-2x+x-1)), so:

2(+2x^2-2x+x-1)

We multiply parentheses

4x^2-4x+2x-2

We add all the numbers together, and all the variables

4x^2-2x-2

Back to the equation:

-(4x^2-2x-2)



We add all the numbers together, and all the variables

4x^2+17x-(4x^2-2x-2)-97=0

We get rid of parentheses

4x^2-4x^2+17x+2x+2-97=0

We add all the numbers together, and all the variables

19x-95=0

We move all terms containing x to the left, all other terms to the right

19x=95

x=95/19

x=5

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