4x2-9Y=8(Y-4+9)

Solution for 4x2-9Y=8(Y-4+9) equation:

4x^2-9=8(-4+9)

We move all terms to the left:

4x^2-9-(8(-4+9))=0

We add all the numbers together, and all the variables

4x^2-9-(85)=0

We add all the numbers together, and all the variables

4x^2-94=0

a = 4; b = 0; c = -94;
Δ = b2-4ac
Δ = 02-4·4·(-94)
Δ = 1504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1504}=\sqrt{16*94}=\sqrt{16}*\sqrt{94}=4\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{94}}{2*4}=\frac{0-4\sqrt{94}}{8}
=-\frac{4\sqrt{94}}{8}
=-\frac{\sqrt{94}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{94}}{2*4}=\frac{0+4\sqrt{94}}{8}
=\frac{4\sqrt{94}}{8}
=\frac{\sqrt{94}}{2}
$