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4x^2-x+16+3x=7x-12-5x
We move all terms to the left:
4x^2-x+16+3x-(7x-12-5x)=0
We add all the numbers together, and all the variables
4x^2-x+3x-(2x-12)+16=0
We add all the numbers together, and all the variables
4x^2+2x-(2x-12)+16=0
We get rid of parentheses
4x^2+2x-2x+12+16=0
We add all the numbers together, and all the variables
4x^2+28=0
a = 4; b = 0; c = +28;
Δ = b2-4ac
Δ = 02-4·4·28
Δ = -448
Delta is less than zero, so there is no solution for the equation
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