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4x^2-x+1=x+3x^2
We move all terms to the left:
4x^2-x+1-(x+3x^2)=0
We add all the numbers together, and all the variables
4x^2-(x+3x^2)-1x+1=0
We get rid of parentheses
4x^2-3x^2-x-1x+1=0
We add all the numbers together, and all the variables
x^2-2x+1=0
a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{2}{2}=1$
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