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4x^2-x-68=0
We add all the numbers together, and all the variables
4x^2-1x-68=0
a = 4; b = -1; c = -68;
Δ = b2-4ac
Δ = -12-4·4·(-68)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-33}{2*4}=\frac{-32}{8} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+33}{2*4}=\frac{34}{8} =4+1/4 $
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