4x2=121

Solution for 4x2=121 equation:

4x^2=121

We move all terms to the left:

4x^2-(121)=0

a = 4; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·4·(-121)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44}{2*4}=\frac{-44}{8}
=-5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44}{2*4}=\frac{44}{8}
=5+1/2
$