4x2=140

Solution for 4x2=140 equation:

4x^2=140

We move all terms to the left:

4x^2-(140)=0

a = 4; b = 0; c = -140;
Δ = b2-4ac
Δ = 02-4·4·(-140)
Δ = 2240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2240}=\sqrt{64*35}=\sqrt{64}*\sqrt{35}=8\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{35}}{2*4}=\frac{0-8\sqrt{35}}{8}
=-\frac{8\sqrt{35}}{8}
=-\sqrt{35}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{35}}{2*4}=\frac{0+8\sqrt{35}}{8}
=\frac{8\sqrt{35}}{8}
=\sqrt{35}
$