4x2=59x+80

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Solution for 4x2=59x+80 equation:



4x^2=59x+80
We move all terms to the left:
4x^2-(59x+80)=0
We get rid of parentheses
4x^2-59x-80=0
a = 4; b = -59; c = -80;
Δ = b2-4ac
Δ = -592-4·4·(-80)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-69}{2*4}=\frac{-10}{8} =-1+1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+69}{2*4}=\frac{128}{8} =16 $

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