4x2=62x+180

Solution for 4x2=62x+180 equation:

4x^2=62x+180

We move all terms to the left:

4x^2-(62x+180)=0

We get rid of parentheses

4x^2-62x-180=0

a = 4; b = -62; c = -180;
Δ = b2-4ac
Δ = -622-4·4·(-180)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-82}{2*4}=\frac{-20}{8}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+82}{2*4}=\frac{144}{8}
=18
$