4x2=82

Solution for 4x2=82 equation:

4x^2=82

We move all terms to the left:

4x^2-(82)=0

a = 4; b = 0; c = -82;
Δ = b2-4ac
Δ = 02-4·4·(-82)
Δ = 1312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1312}=\sqrt{16*82}=\sqrt{16}*\sqrt{82}=4\sqrt{82}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{82}}{2*4}=\frac{0-4\sqrt{82}}{8}
=-\frac{4\sqrt{82}}{8}
=-\frac{\sqrt{82}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{82}}{2*4}=\frac{0+4\sqrt{82}}{8}
=\frac{4\sqrt{82}}{8}
=\frac{\sqrt{82}}{2}
$