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4x^2=x-3=0
We move all terms to the left:
4x^2-(x-3)=0
We get rid of parentheses
4x^2-x+3=0
We add all the numbers together, and all the variables
4x^2-1x+3=0
a = 4; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·4·3
Δ = -47
Delta is less than zero, so there is no solution for the equation
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