4x2x=2(x+2)+2(4x-5)

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Solution for 4x2x=2(x+2)+2(4x-5) equation: 



4x^2x=2(x+2)+2(4x-5)

We move all terms to the left:

4x^2x-(2(x+2)+2(4x-5))=0



We calculate terms in parentheses: -(2(x+2)+2(4x-5)), so:

2(x+2)+2(4x-5)

We multiply parentheses

2x+8x+4-10

We add all the numbers together, and all the variables

10x-6

Back to the equation:

-(10x-6)



We get rid of parentheses

4x^2x-10x+6=0

We move all terms containing x to the left, all other terms to the right

4x^2x-10x=-6

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