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4x=(2-7(4-2x))/(3)
We move all terms to the left:
4x-((2-7(4-2x))/(3))=0
We add all the numbers together, and all the variables
4x-((2-7(-2x+4))/3)=0
We multiply all the terms by the denominator
4x*3)-((2-7(-2x+4))=0
Wy multiply elements
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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