4x=10+2y;-5/4x+y=7/4

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Solution for 4x=10+2y;-5/4x+y=7/4 system of equations: 


  • /| 4*x-(2*y)-10 = 0| (-5/4)*x+y-(7/4) = 0
  • We try to solve the equation: 4*x-(2*y)-10 = 0
  • 4*x-2*y-10 = 0 // - 4*x-10
  • -2*y = -(4*x-10) // : -2
  • y = (-(4*x-10))/(-2)
  • y = (10-(4*x))/(-2)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (10-(4*x))/(-2)+(-5/4)*x-(7/4) = 0| y = (10-(4*x))/(-2)
  • (10-4*x)/(-2)+(-5*x)/4-7/4 = 0
  • 3/4*x-5-7/4 = 0
  • 3/4*x-27/4 = 0
  • 3/4*x-27/4 = 0 // + 27/4
  • 3/4*x = 27/4 // : 3/4
  • x = 27/4/3/4
  • x = 9
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (10-(4*x))/(-2): 
  • y = (10-(4*9))/(-2)
  • y = (10-36)/(-2)
  • y = -26/(-2)
  • y = 13
  • We get a system of equations:
  • /| y = 13| x = 9

 

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