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4x=11/2x=3
We move all terms to the left:
4x-(11/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-(+11/2x)=0
We get rid of parentheses
4x-11/2x=0
We multiply all the terms by the denominator
4x*2x-11=0
Wy multiply elements
8x^2-11=0
a = 8; b = 0; c = -11;
Δ = b2-4ac
Δ = 02-4·8·(-11)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{22}}{2*8}=\frac{0-4\sqrt{22}}{16} =-\frac{4\sqrt{22}}{16} =-\frac{\sqrt{22}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{22}}{2*8}=\frac{0+4\sqrt{22}}{16} =\frac{4\sqrt{22}}{16} =\frac{\sqrt{22}}{4} $
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