4x=12+3(2x+2)=4(2x+20)

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Solution for 4x=12+3(2x+2)=4(2x+20) equation:



4x=12+3(2x+2)=4(2x+20)
We move all terms to the left:
4x-(12+3(2x+2))=0
We calculate terms in parentheses: -(12+3(2x+2)), so:
12+3(2x+2)
determiningTheFunctionDomain 3(2x+2)+12
We multiply parentheses
6x+6+12
We add all the numbers together, and all the variables
6x+18
Back to the equation:
-(6x+18)
We get rid of parentheses
4x-6x-18=0
We add all the numbers together, and all the variables
-2x-18=0
We move all terms containing x to the left, all other terms to the right
-2x=18
x=18/-2
x=-9

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