4x=12+3(2x+2)=4(2x+20)

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Solution for 4x=12+3(2x+2)=4(2x+20) equation: 



4x=12+3(2x+2)=4(2x+20)

We move all terms to the left:

4x-(12+3(2x+2))=0



We calculate terms in parentheses: -(12+3(2x+2)), so:

12+3(2x+2)

determiningTheFunctionDomain
3(2x+2)+12

We multiply parentheses

6x+6+12

We add all the numbers together, and all the variables

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

4x-6x-18=0

We add all the numbers together, and all the variables

-2x-18=0

We move all terms containing x to the left, all other terms to the right

-2x=18

x=18/-2

x=-9

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