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4x=12/9x
We move all terms to the left:
4x-(12/9x)=0
Domain of the equation: 9x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-(+12/9x)=0
We get rid of parentheses
4x-12/9x=0
We multiply all the terms by the denominator
4x*9x-12=0
Wy multiply elements
36x^2-12=0
a = 36; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·36·(-12)
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*36}=\frac{0-24\sqrt{3}}{72} =-\frac{24\sqrt{3}}{72} =-\frac{\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*36}=\frac{0+24\sqrt{3}}{72} =\frac{24\sqrt{3}}{72} =\frac{\sqrt{3}}{3} $
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