4x=14-(x+2+x+4)2

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Solution for 4x=14-(x+2+x+4)2 equation: 



4x=14-(x+2+x+4)2

We move all terms to the left:

4x-(14-(x+2+x+4)2)=0

We add all the numbers together, and all the variables

4x-(14-(2x+6)2)=0



We calculate terms in parentheses: -(14-(2x+6)2), so:

14-(2x+6)2

determiningTheFunctionDomain
-(2x+6)2+14

We multiply parentheses

-4x-12+14

We add all the numbers together, and all the variables

-4x+2

Back to the equation:

-(-4x+2)



We get rid of parentheses

4x+4x-2=0

We add all the numbers together, and all the variables

8x-2=0

We move all terms containing x to the left, all other terms to the right

8x=2

x=2/8

x=1/4

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