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4x=24-4/3x
We move all terms to the left:
4x-(24-4/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-(-4/3x+24)=0
We get rid of parentheses
4x+4/3x-24=0
We multiply all the terms by the denominator
4x*3x-24*3x+4=0
Wy multiply elements
12x^2-72x+4=0
a = 12; b = -72; c = +4;
Δ = b2-4ac
Δ = -722-4·12·4
Δ = 4992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4992}=\sqrt{64*78}=\sqrt{64}*\sqrt{78}=8\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-8\sqrt{78}}{2*12}=\frac{72-8\sqrt{78}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+8\sqrt{78}}{2*12}=\frac{72+8\sqrt{78}}{24} $
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