4x=3(3x+12)=140

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Solution for 4x=3(3x+12)=140 equation: 



4x=3(3x+12)=140

We move all terms to the left:

4x-(3(3x+12))=0



We calculate terms in parentheses: -(3(3x+12)), so:

3(3x+12)

We multiply parentheses

9x+36

Back to the equation:

-(9x+36)



We get rid of parentheses

4x-9x-36=0

We add all the numbers together, and all the variables

-5x-36=0

We move all terms containing x to the left, all other terms to the right

-5x=36

x=36/-5

x=-7+1/5

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