4x=3(4x+1)-35

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Solution for 4x=3(4x+1)-35 equation: 



4x=3(4x+1)-35

We move all terms to the left:

4x-(3(4x+1)-35)=0



We calculate terms in parentheses: -(3(4x+1)-35), so:

3(4x+1)-35

We multiply parentheses

12x+3-35

We add all the numbers together, and all the variables

12x-32

Back to the equation:

-(12x-32)



We get rid of parentheses

4x-12x+32=0

We add all the numbers together, and all the variables

-8x+32=0

We move all terms containing x to the left, all other terms to the right

-8x=-32

x=-32/-8

x=+4

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