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4x=5/2x+18
We move all terms to the left:
4x-(5/2x+18)=0
Domain of the equation: 2x+18)!=0We get rid of parentheses
x∈R
4x-5/2x-18=0
We multiply all the terms by the denominator
4x*2x-18*2x-5=0
Wy multiply elements
8x^2-36x-5=0
a = 8; b = -36; c = -5;
Δ = b2-4ac
Δ = -362-4·8·(-5)
Δ = 1456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1456}=\sqrt{16*91}=\sqrt{16}*\sqrt{91}=4\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{91}}{2*8}=\frac{36-4\sqrt{91}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{91}}{2*8}=\frac{36+4\sqrt{91}}{16} $
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