4x=x+(2x-3)+(3x-4)

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Solution for 4x=x+(2x-3)+(3x-4) equation: 



4x=x+(2x-3)+(3x-4)

We move all terms to the left:

4x-(x+(2x-3)+(3x-4))=0



We calculate terms in parentheses: -(x+(2x-3)+(3x-4)), so:

x+(2x-3)+(3x-4)

We get rid of parentheses

x+2x+3x-3-4

We add all the numbers together, and all the variables

6x-7

Back to the equation:

-(6x-7)



We get rid of parentheses

4x-6x+7=0

We add all the numbers together, and all the variables

-2x+7=0

We move all terms containing x to the left, all other terms to the right

-2x=-7

x=-7/-2

x=3+1/2

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