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4xxx=3x(x+1)
We move all terms to the left:
4xxx-(3x(x+1))=0
We calculate terms in parentheses: -(3x(x+1)), so:We get rid of parentheses
3x(x+1)
We multiply parentheses
3x^2+3x
Back to the equation:
-(3x^2+3x)
-3x^2+4xxx-3x=0
We add all the numbers together, and all the variables
-3x^2-3x+4xxx=0
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