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4y(2)=5.76
We move all terms to the left:
4y(2)-(5.76)=0
We add all the numbers together, and all the variables
4y^2-5.76=0
a = 4; b = 0; c = -5.76;
Δ = b2-4ac
Δ = 02-4·4·(-5.76)
Δ = 92.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{92.16}}{2*4}=\frac{0-\sqrt{92.16}}{8} =-\frac{\sqrt{}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{92.16}}{2*4}=\frac{0+\sqrt{92.16}}{8} =\frac{\sqrt{}}{8} $
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