4y(y-3)=y-12

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Solution for 4y(y-3)=y-12 equation: 



4y(y-3)=y-12

We move all terms to the left:

4y(y-3)-(y-12)=0

We multiply parentheses

4y^2-12y-(y-12)=0

We get rid of parentheses

4y^2-12y-y+12=0

We add all the numbers together, and all the variables

4y^2-13y+12=0

a = 4; b = -13; c = +12;
Δ = b2-4ac
Δ = -132-4·4·12
Δ = -23
Delta is less than zero, so there is no solution for the equation

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