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4y*12y=324
We move all terms to the left:
4y*12y-(324)=0
Wy multiply elements
48y^2-324=0
a = 48; b = 0; c = -324;
Δ = b2-4ac
Δ = 02-4·48·(-324)
Δ = 62208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{62208}=\sqrt{20736*3}=\sqrt{20736}*\sqrt{3}=144\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144\sqrt{3}}{2*48}=\frac{0-144\sqrt{3}}{96} =-\frac{144\sqrt{3}}{96} =-\frac{3\sqrt{3}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144\sqrt{3}}{2*48}=\frac{0+144\sqrt{3}}{96} =\frac{144\sqrt{3}}{96} =\frac{3\sqrt{3}}{2} $
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