4y+(3y+13)=118

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Solution for 4y+(3y+13)=118 equation:



4y+(3y+13)=118
We move all terms to the left:
4y+(3y+13)-(118)=0
We get rid of parentheses
4y+3y+13-118=0
We add all the numbers together, and all the variables
7y-105=0
We move all terms containing y to the left, all other terms to the right
7y=105
y=105/7
y=15

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