4y+(3y+13)=118

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Solution for 4y+(3y+13)=118 equation: 



4y+(3y+13)=118

We move all terms to the left:

4y+(3y+13)-(118)=0

We get rid of parentheses

4y+3y+13-118=0

We add all the numbers together, and all the variables

7y-105=0

We move all terms containing y to the left, all other terms to the right

7y=105

y=105/7

y=15

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