4y+(3y-7)=2y+(y+13)

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Solution for 4y+(3y-7)=2y+(y+13) equation: 



4y+(3y-7)=2y+(y+13)

We move all terms to the left:

4y+(3y-7)-(2y+(y+13))=0

We get rid of parentheses

4y+3y-(2y+(y+13))-7=0



We calculate terms in parentheses: -(2y+(y+13)), so:

2y+(y+13)

We get rid of parentheses

2y+y+13

We add all the numbers together, and all the variables

3y+13

Back to the equation:

-(3y+13)



We add all the numbers together, and all the variables

7y-(3y+13)-7=0

We get rid of parentheses

7y-3y-13-7=0

We add all the numbers together, and all the variables

4y-20=0

We move all terms containing y to the left, all other terms to the right

4y=20

y=20/4

y=5

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