4y+(4y-2)=3(y+1)

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Solution for 4y+(4y-2)=3(y+1) equation: 



4y+(4y-2)=3(y+1)

We move all terms to the left:

4y+(4y-2)-(3(y+1))=0

We get rid of parentheses

4y+4y-(3(y+1))-2=0



We calculate terms in parentheses: -(3(y+1)), so:

3(y+1)

We multiply parentheses

3y+3

Back to the equation:

-(3y+3)



We add all the numbers together, and all the variables

8y-(3y+3)-2=0

We get rid of parentheses

8y-3y-3-2=0

We add all the numbers together, and all the variables

5y-5=0

We move all terms containing y to the left, all other terms to the right

5y=5

y=5/5

y=1

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