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4y+12=3-(y+6)
We move all terms to the left:
4y+12-(3-(y+6))=0
We calculate terms in parentheses: -(3-(y+6)), so:We get rid of parentheses
3-(y+6)
determiningTheFunctionDomain -(y+6)+3
We get rid of parentheses
-y-6+3
We add all the numbers together, and all the variables
-1y-3
Back to the equation:
-(-1y-3)
4y+1y+3+12=0
We add all the numbers together, and all the variables
5y+15=0
We move all terms containing y to the left, all other terms to the right
5y=-15
y=-15/5
y=-3
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