4y+2(2y+3)=10y-15

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Solution for 4y+2(2y+3)=10y-15 equation: 



4y+2(2y+3)=10y-15

We move all terms to the left:

4y+2(2y+3)-(10y-15)=0

We multiply parentheses

4y+4y-(10y-15)+6=0

We get rid of parentheses

4y+4y-10y+15+6=0

We add all the numbers together, and all the variables

-2y+21=0

We move all terms containing y to the left, all other terms to the right

-2y=-21

y=-21/-2

y=10+1/2

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