4y+2(y+1)=16

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Solution for 4y+2(y+1)=16 equation: 



4y+2(y+1)=16

We move all terms to the left:

4y+2(y+1)-(16)=0

We multiply parentheses

4y+2y+2-16=0

We add all the numbers together, and all the variables

6y-14=0

We move all terms containing y to the left, all other terms to the right

6y=14

y=14/6

y=2+1/3

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