4y+2(y-2)=10y-6(y-10)

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Solution for 4y+2(y-2)=10y-6(y-10) equation: 



4y+2(y-2)=10y-6(y-10)

We move all terms to the left:

4y+2(y-2)-(10y-6(y-10))=0

We multiply parentheses

4y+2y-(10y-6(y-10))-4=0



We calculate terms in parentheses: -(10y-6(y-10)), so:

10y-6(y-10)

We multiply parentheses

10y-6y+60

We add all the numbers together, and all the variables

4y+60

Back to the equation:

-(4y+60)



We add all the numbers together, and all the variables

6y-(4y+60)-4=0

We get rid of parentheses

6y-4y-60-4=0

We add all the numbers together, and all the variables

2y-64=0

We move all terms containing y to the left, all other terms to the right

2y=64

y=64/2

y=32

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