4y+2(y-8)=8y-4(y-10)

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Solution for 4y+2(y-8)=8y-4(y-10) equation:


Simplifying
4y + 2(y + -8) = 8y + -4(y + -10)

Reorder the terms:
4y + 2(-8 + y) = 8y + -4(y + -10)
4y + (-8 * 2 + y * 2) = 8y + -4(y + -10)
4y + (-16 + 2y) = 8y + -4(y + -10)

Reorder the terms:
-16 + 4y + 2y = 8y + -4(y + -10)

Combine like terms: 4y + 2y = 6y
-16 + 6y = 8y + -4(y + -10)

Reorder the terms:
-16 + 6y = 8y + -4(-10 + y)
-16 + 6y = 8y + (-10 * -4 + y * -4)
-16 + 6y = 8y + (40 + -4y)

Reorder the terms:
-16 + 6y = 40 + 8y + -4y

Combine like terms: 8y + -4y = 4y
-16 + 6y = 40 + 4y

Solving
-16 + 6y = 40 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-16 + 6y + -4y = 40 + 4y + -4y

Combine like terms: 6y + -4y = 2y
-16 + 2y = 40 + 4y + -4y

Combine like terms: 4y + -4y = 0
-16 + 2y = 40 + 0
-16 + 2y = 40

Add '16' to each side of the equation.
-16 + 16 + 2y = 40 + 16

Combine like terms: -16 + 16 = 0
0 + 2y = 40 + 16
2y = 40 + 16

Combine like terms: 40 + 16 = 56
2y = 56

Divide each side by '2'.
y = 28

Simplifying
y = 28

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