4y+2+2(3y-7)=3(3y-1)

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Solution for 4y+2+2(3y-7)=3(3y-1) equation: 



4y+2+2(3y-7)=3(3y-1)

We move all terms to the left:

4y+2+2(3y-7)-(3(3y-1))=0

We multiply parentheses

4y+6y-(3(3y-1))-14+2=0



We calculate terms in parentheses: -(3(3y-1)), so:

3(3y-1)

We multiply parentheses

9y-3

Back to the equation:

-(9y-3)



We add all the numbers together, and all the variables

10y-(9y-3)-12=0

We get rid of parentheses

10y-9y+3-12=0

We add all the numbers together, and all the variables

y-9=0

We move all terms containing y to the left, all other terms to the right

y=9

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