4y+2-2(-4y-2)=4(y-3)

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Solution for 4y+2-2(-4y-2)=4(y-3) equation: 



4y+2-2(-4y-2)=4(y-3)

We move all terms to the left:

4y+2-2(-4y-2)-(4(y-3))=0

We multiply parentheses

4y+8y-(4(y-3))+4+2=0



We calculate terms in parentheses: -(4(y-3)), so:

4(y-3)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)



We add all the numbers together, and all the variables

12y-(4y-12)+6=0

We get rid of parentheses

12y-4y+12+6=0

We add all the numbers together, and all the variables

8y+18=0

We move all terms containing y to the left, all other terms to the right

8y=-18

y=-18/8

y=-2+1/4

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