4y+20-5y-3=10y+8-29

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Solution for 4y+20-5y-3=10y+8-29 equation: 



4y+20-5y-3=10y+8-29

We move all terms to the left:

4y+20-5y-3-(10y+8-29)=0

We add all the numbers together, and all the variables

4y-5y-(10y-21)+20-3=0

We add all the numbers together, and all the variables

-1y-(10y-21)+17=0

We get rid of parentheses

-1y-10y+21+17=0

We add all the numbers together, and all the variables

-11y+38=0

We move all terms containing y to the left, all other terms to the right

-11y=-38

y=-38/-11

y=3+5/11

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