4y+28=6(y+4)

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Solution for 4y+28=6(y+4) equation: 



4y+28=6(y+4)

We move all terms to the left:

4y+28-(6(y+4))=0



We calculate terms in parentheses: -(6(y+4)), so:

6(y+4)

We multiply parentheses

6y+24

Back to the equation:

-(6y+24)



We get rid of parentheses

4y-6y-24+28=0

We add all the numbers together, and all the variables

-2y+4=0

We move all terms containing y to the left, all other terms to the right

-2y=-4

y=-4/-2

y=+2

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