4y+28=8y-12

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Solution for 4y+28=8y-12 equation:



4y+28=8y-12
We move all terms to the left:
4y+28-(8y-12)=0
We get rid of parentheses
4y-8y+12+28=0
We add all the numbers together, and all the variables
-4y+40=0
We move all terms containing y to the left, all other terms to the right
-4y=-40
y=-40/-4
y=+10

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