4y+28y=(6y-10)

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Solution for 4y+28y=(6y-10) equation: 



4y+28y=(6y-10)

We move all terms to the left:

4y+28y-((6y-10))=0

We add all the numbers together, and all the variables

32y-((6y-10))=0



We calculate terms in parentheses: -((6y-10)), so:

(6y-10)

We get rid of parentheses

6y-10

Back to the equation:

-(6y-10)



We get rid of parentheses

32y-6y+10=0

We add all the numbers together, and all the variables

26y+10=0

We move all terms containing y to the left, all other terms to the right

26y=-10

y=-10/26

y=-5/13

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