4y+2=(y-2)=8

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Solution for 4y+2=(y-2)=8 equation: 



4y+2=(y-2)=8

We move all terms to the left:

4y+2-((y-2))=0



We calculate terms in parentheses: -((y-2)), so:

(y-2)

We get rid of parentheses

y-2

Back to the equation:

-(y-2)



We get rid of parentheses

4y-y+2+2=0

We add all the numbers together, and all the variables

3y+4=0

We move all terms containing y to the left, all other terms to the right

3y=-4

y=-4/3

y=-1+1/3

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