4y+2=-2(y-1)

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Solution for 4y+2=-2(y-1) equation: 



4y+2=-2(y-1)

We move all terms to the left:

4y+2-(-2(y-1))=0



We calculate terms in parentheses: -(-2(y-1)), so:

-2(y-1)

We multiply parentheses

-2y+2

Back to the equation:

-(-2y+2)



We get rid of parentheses

4y+2y-2+2=0

We add all the numbers together, and all the variables

6y=0

y=0/6

y=0

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