4y+2x=20;15y+5x=60

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x+3y=14

Solution for 4y+2x=20;15y+5x=60 system of equations: 


  • /| 2*x+4*y-20 = 0| 5*x+15*y-60 = 0
  • We try to solve the equation: 2*x+4*y-20 = 0
  • 2*x+4*y-20 = 0 // - 2*x-20
  • 4*y = -(2*x-20) // : 4
  • y = (-(2*x-20))/4
  • y = (20-(2*x))/4
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 15*((20-(2*x))/4)+5*x-60 = 0| y = (20-(2*x))/4
  • (15*(20-2*x))/4+5*x-60 = 0
  • 75-5/2*x-60 = 0
  • 15-5/2*x = 0
  • 15-5/2*x = 0 // - 15
  • -5/2*x = -15 // : -5/2
  • x = -15/(-5/2)
  • x = 6
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (20-(2*x))/4: 
  • y = (20-(2*6))/4
  • y = (20-12)/4
  • y = 8/4
  • y = 2
  • We get a system of equations:
  • /| y = 2| x = 6

 

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