4y+2y=3(2y+20)

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Solution for 4y+2y=3(2y+20) equation: 



4y+2y=3(2y+20)

We move all terms to the left:

4y+2y-(3(2y+20))=0

We add all the numbers together, and all the variables

6y-(3(2y+20))=0



We calculate terms in parentheses: -(3(2y+20)), so:

3(2y+20)

We multiply parentheses

6y+60

Back to the equation:

-(6y+60)



We get rid of parentheses

6y-6y-60=0

We add all the numbers together, and all the variables

-60!=0

There is no solution for this equation

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