4y+3+(2y+4)=10y-13

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Solution for 4y+3+(2y+4)=10y-13 equation: 



4y+3+(2y+4)=10y-13

We move all terms to the left:

4y+3+(2y+4)-(10y-13)=0

We get rid of parentheses

4y+2y-10y+4+13+3=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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