4y+32=-3(y-6)

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Solution for 4y+32=-3(y-6) equation: 



4y+32=-3(y-6)

We move all terms to the left:

4y+32-(-3(y-6))=0



We calculate terms in parentheses: -(-3(y-6)), so:

-3(y-6)

We multiply parentheses

-3y+18

Back to the equation:

-(-3y+18)



We get rid of parentheses

4y+3y-18+32=0

We add all the numbers together, and all the variables

7y+14=0

We move all terms containing y to the left, all other terms to the right

7y=-14

y=-14/7

y=-2

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