4y+32=-8(y+5)

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Solution for 4y+32=-8(y+5) equation:



4y+32=-8(y+5)
We move all terms to the left:
4y+32-(-8(y+5))=0
We calculate terms in parentheses: -(-8(y+5)), so:
-8(y+5)
We multiply parentheses
-8y-40
Back to the equation:
-(-8y-40)
We get rid of parentheses
4y+8y+40+32=0
We add all the numbers together, and all the variables
12y+72=0
We move all terms containing y to the left, all other terms to the right
12y=-72
y=-72/12
y=-6

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