4y+33=25+7y

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Solution for 4y+33=25+7y equation:



4y+33=25+7y
We move all terms to the left:
4y+33-(25+7y)=0
We add all the numbers together, and all the variables
4y-(7y+25)+33=0
We get rid of parentheses
4y-7y-25+33=0
We add all the numbers together, and all the variables
-3y+8=0
We move all terms containing y to the left, all other terms to the right
-3y=-8
y=-8/-3
y=2+2/3

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