4y+33=25+7y

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Solution for 4y+33=25+7y equation: 



4y+33=25+7y

We move all terms to the left:

4y+33-(25+7y)=0

We add all the numbers together, and all the variables

4y-(7y+25)+33=0

We get rid of parentheses

4y-7y-25+33=0

We add all the numbers together, and all the variables

-3y+8=0

We move all terms containing y to the left, all other terms to the right

-3y=-8

y=-8/-3

y=2+2/3

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